(2+3y)^2-2*(2+3y)*y=7

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Solution for (2+3y)^2-2*(2+3y)*y=7 equation: 



(2+3y)^2-2(2+3y)*y=7

We move all terms to the left:

(2+3y)^2-2(2+3y)*y-(7)=0

We add all the numbers together, and all the variables

(3y+2)^2-2(3y+2)*y-7=0

We multiply parentheses

-6y^2+(3y+2)^2-4y-7=0

We add all the numbers together, and all the variables

-6y^2-4y+(3y+2)^2-7=0

We move all terms containing y to the left, all other terms to the right

-6y^2-4y+(3y+2)^2=7

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